Advertisements
Advertisements
प्रश्न
The first term of an A.P. is p and its common difference is q. Find its 10th term.
उत्तर
Here, we are given,
First term (a) = p
Common difference (d) = q
We need to find the 10th term (an).
As we know,
an = a + (n - 1) d
So, for 10th term (n = 10), we get,
a10 = p + ( 10 - 1 ) q
= p + 9q
Therefore, a10 = p + 9q
APPEARS IN
संबंधित प्रश्न
If the mth term of an A.P. is 1/n and the nth term is 1/m, show that the sum of mn terms is (mn + 1)
Find the four numbers in A.P., whose sum is 50 and in which the greatest number is 4 times the least.
Which term of the AP `20, 19 1/4 , 18 1/2 , 17 3/4 ` ,..... is the first negative term?
The 8th term of an AP is zero. Prove that its 38th term is triple its 18th term.
If (3y – 1), (3y + 5) and (5y + 1) are three consecutive terms of an AP then find the value of y.
If the sum of first m terms of an AP is ( 2m2 + 3m) then what is its second term?
In an A.P. 17th term is 7 more than its 10th term. Find the common difference.
Write the value of a30 − a10 for the A.P. 4, 9, 14, 19, ....
For an A.P., If t1 = 1 and tn = 149 then find Sn.
Activitry :- Here t1= 1, tn = 149, Sn = ?
Sn = `"n"/2 (square + square)`
= `"n"/2 xx square`
= `square` n, where n = 75
Which term of the AP: –2, –7, –12,... will be –77? Find the sum of this AP upto the term –77.