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The first term of an A.P. is 5, the last term is 45 and the sum of its terms is 1000. Find the number of terms and the common difference of the A.P. - Mathematics

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प्रश्न

The first term of an A.P. is 5, the last term is 45 and the sum of its terms is 1000. Find the number of terms and the common difference of the A.P.

योग

उत्तर

First term a = 5

Last term l = 45

Sum of terms = 1000

Let there be n terms in this A.P.

Now, sum of first n terms = `n/2 [a + l]`

`=> 1000 = n/2 [5 + 45]`

`=>` 2000 = n × 50

`=>` n = 40

l = a + (n – 1)d

`=>` 45 = 5 + (40 – 1)d

`=>` 40 = 39d

`=> d = 40/39`

Hence, number of terms are 40 and common difference is `40/39`.

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अध्याय 10: Arithmetic Progression - Exercise 10 (C) [पृष्ठ १४३]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 10 Arithmetic Progression
Exercise 10 (C) | Q 7 | पृष्ठ १४३
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