Question

The following data was obtained for chemical reaction given below at 975 K.

\[\ce{2NO(g) + 2H2(g) -> N2(g) + 2H2O(g)}\]

	[NO]	[H2]	Rate
	Mol L-1	Mol L-1	Mol L-1 s-1
(1)	8 × 10-5	8 × 10-5	7 × 10-9
(2)	24 × 10-5	8 × 10-5	2.1 × 10-8
(3)	24 × 10-5	32 × 10-5	8.4 × 10-8

The order of the reaction with respect to NO is ______. (Integer answer)

विकल्प

• 1

• 5

• 2

• 0

Answer 1

The order of the reaction with respect to NO is 1.

Explanation:

Let the order of the reaction with respect to NO and H₂ are x and y respectively. From experiment (1) and (2).

`"R"_2/"R"_1 = (k["NO"]^x ["H"_2]^y)/(k["NO"]^x ["H"_2]^y)`

`therefore (2.1 xx 10^-8)/(7 xx 10^-9) = (k[24 xx 10^-5]^x [8 xx 10^-5]^y)/(k[8 xx 10^-5]^x [8 xx 10^-5]^y)`

`therefore (2.1 xx 10^-8)/(7 xx 10^-9) = (cancel(k)[24 xx cancel(10^-5)]^x cancel([8 xx 10^-5]^y))/(cancel(k)[8 xx cancel(10^-5)]^x cancel([8 xx 10^-5]^y))`

`therefore (2.1 xx 10^-8)/(7 xx 10^-9) = (24/8)^x`

`therefore (21 xx 10^-9)/(7 xx 10^-9) = (3)^x`

∴ (3)¹ = (3)^x

∴ x = 1