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प्रश्न
The function of a satellite launcher is based on Newton's second law of motion.
विकल्प
Right
Wrong
उत्तर
The function of a satellite launcher is based on Newton's second law of motion- Wrong
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संबंधित प्रश्न
Fill in the blank and explain the statement with reasoning:
If the height of the orbit of a satellite from the earth surface is increased, the tangential velocity of the satellite will ......
Why are geostationary satellites not useful for studies of polar regions?
Solve the problem.
How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?
Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface.
Name the first artificial satellite sent by Russia in space.
Calculate the critical velocity of the satellite to be located at 35780 km above the surface of earth.
What is Medium Earth Orbit?
Distinguish between:
High Earth orbit - Medium Earth orbit.
Write functions of Military satellite and Navigational satellite.
Note the relationship between the entries in all the three columns in the table and rewrite the table.
Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
Earth’s surface (average) | 8.8 | 0.225 |
Mount Everest | 36.6 | 9.81 |
Maximum height ever reached by manmade balloon | 400 | 9.8 |
Orbit of a typical weather satellite | 35700 | 9.77 |
Orbit of communication satellite | 0 | 8.7 |
What is microgravity?
The orbital velocity of the satellite depends on its ______.
Complete the Following table.
Sr. no. | Type of Satellite | The names of Indian Satellite and launcher |
(1) | Navigational Satellite | Satellite: ______ |
Launcher: ______ | ||
(2) | Earth Observation Satellite | Satellite: ______ |
Launcher: ______ |
Complete the following equations:
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)