हिंदी

The given table shows the freezing points in °F of different gases at sea level. Convert each of these into °C to the nearest integral value using the relation and complete the table - Mathematics

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प्रश्न

The given table shows the freezing points in °F of different gases at sea level. Convert each of these into °C to the nearest integral value using the relation and complete the table,

C = `5/9 (F - 32)`

Gas Freezing Point at
Sea Level (°F)
Freezing Point at
Sea Level (°C)
Hydrogen –435  
Krypton –251  
Oxygen –369  
Helium –458  
Argon –309  
योग

उत्तर

We have, C = `5/9 (F - 32)`

For Hydrogen, put F = (–435)

⇒ C = `5/9 (- 435 - 32)`

= `5/9 xx (-467)`

= –259.44

⇒ C = –259.44

For Krypton, put F = (–251)

⇒ C = `5/9 (-251 - 32)`

= `5/9 xx (-283)`

=  –157.22

⇒ C = –157.22

For Oxygen, put F = (–369)

⇒ C = `5/9 (-369 - 32)`

= `5/9 xx (-401)`

=  –222.7

⇒ C = –223

For Helium, put F = (–458)

⇒ C = `5/9 (-458 - 32)`

= `5/9 xx (-490)`

=  –272.22

⇒ C = –272.22

For Argon, put F = (–309)

⇒ C = `5/9 (-309 - 32)`

= `5/9 xx (-341)`

=  –189.44

⇒ C = –189.44

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अध्याय 1: Integers - Exercise [पृष्ठ २१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 7
अध्याय 1 Integers
Exercise | Q 129 | पृष्ठ २१

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