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प्रश्न
The given table shows the freezing points in °F of different gases at sea level. Convert each of these into °C to the nearest integral value using the relation and complete the table,
C = `5/9 (F - 32)`
Gas | Freezing Point at Sea Level (°F) |
Freezing Point at Sea Level (°C) |
Hydrogen | –435 | |
Krypton | –251 | |
Oxygen | –369 | |
Helium | –458 | |
Argon | –309 |
उत्तर
We have, C = `5/9 (F - 32)`
For Hydrogen, put F = (–435)
⇒ C = `5/9 (- 435 - 32)`
= `5/9 xx (-467)`
= –259.44
⇒ C = –259.44
For Krypton, put F = (–251)
⇒ C = `5/9 (-251 - 32)`
= `5/9 xx (-283)`
= –157.22
⇒ C = –157.22
For Oxygen, put F = (–369)
⇒ C = `5/9 (-369 - 32)`
= `5/9 xx (-401)`
= –222.7
⇒ C = –223
For Helium, put F = (–458)
⇒ C = `5/9 (-458 - 32)`
= `5/9 xx (-490)`
= –272.22
⇒ C = –272.22
For Argon, put F = (–309)
⇒ C = `5/9 (-309 - 32)`
= `5/9 xx (-341)`
= –189.44
⇒ C = –189.44
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