Question

The \[\ce{H - O - H}\] bond angle in a water molecule is about ______.

विकल्प

• 107°18'

• 120°

• 109°28'

• 104°35'

Answer 1

The \[\ce{H - O - H}\] bond angle in a water molecule is about 104°35'.

Explanation:

The \[\ce{H - O - H}\] bond angle in the water molecule is approximately 104 °35' (caused by the attraction of two lone electron pairs).