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प्रश्न
The joint equation of the pair of lines passing through (2,3) and parallel to the coordinate axes is
- xy − 3x − 2y + 6 = 0
- xy + 3x + 2y + 6 = 0
- xy = 0
- xy − 3x − 2y − 6 = 0
योग
उत्तर
Equation of the coordinate axes are x = 0 and y = 0.
The equations of the lines passing through (2, 3) and parallel to coordinate axes are,
x = 2 and y = 3.
i.e. x − 2 = 0 and y − 3 = 0
The joint equation is given as
(x − 2) (y − 3) = 0
xy − 3x − 2y + 6 = 0
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