Question

The magnitude of the magnetic field due to a circular coil of radius R carrying a current I at an axial distance x from the centre is ______.

विकल्प

• B = `(mu_0"IR"^3)/(2(x^2 + "R"^2)^(3/2))`

• B = `(mu_0"IR"^2)/(2(x^2 + "R"^2)^(3/5))`

• B = `(mu_0"IR"^2)/(2(x^2 + "R"^2)^(3/2))`

• B = `(mu_0"IR"^2)/(3(x^2 + "R"^2)^(3/2))`

Answer 1

The magnitude of the magnetic field due to a circular coil of radius R carrying a current I at an axial distance x from the centre is `underline("B" = (mu_0"IR"^2)/(2(x^2 + "R"^2)^(3/2)))`.

Explanation:

Magnetic field at a point located at a distance x from the center of the coil of radius R carrying current along its axis is B = `(mu_0"IR"^2)/(2(x^2 + "R"^2)^(3/2))`.