हिंदी

The Midpoint of the Line Segment Joining the Points P (2 , M) and Q (N , 4) is R (3 , 5) - Mathematics

Advertisements
Advertisements

प्रश्न

The midpoint of the line segment joining the points P (2 , m) and Q (n , 4) is R (3 , 5) . Find the values of m and n.

योग

उत्तर

Given : PR : RQ = 1 : 1

Coordinates of R are ,

R (3 , 5) = R `((2 + "n")/2 , ("m" + 4)/2)`

B = `(2 + "n")/2  , 5 = ("m" + 4)/2`

6 = 2 + n     , 10 = m + 4

n  = 4 , m = 6

The values of m and n are 6 and 4  respectively.

shaalaa.com
The Mid-point of a Line Segment (Mid-point Formula)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Distance and Section Formulae - Exercise 12.3

APPEARS IN

फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 12 Distance and Section Formulae
Exercise 12.3 | Q 26

संबंधित प्रश्न

The points (2, –1), (–1, 4) and (–2, 2) are mid-points of the sides of a triangle. Find its vertices.


Calculate the co-ordinates of the centroid of the triangle ABC, if A = (7, –2), B = (0, 1) and C =(–1, 4).


The mid-point of the line segment joining (2a, 4) and (–2, 2b) is (1, 2a + 1). Find the values of a and b.


Point P is the centre of the circle and AB is a diameter . Find the coordinates of point B if coordinates of point A and P are (2, –3) and (–2, 0) respectively.


Complete the table below the graph with the help of the following graph.

Sr. No. First point Second point Co-ordinates of first point (x1 , y1) Co-ordinates of second point (x2 , y2) `(y_2 - y_2)/(x_2 - x_2)`
1 C E (1, 0) (3,4) `4/2=2`
2 A B (-1,-4) (0,-2) `2/1 = 2`
3 B D (0,-2) (2,2) `4/2=2`

A( 4, 2), B(-2, -6) and C(l, 1) are the vertices of triangle ABC. Find its centroid and the length of the median through C. 


The midpoints of three sides of a triangle are (1, 2), (2, -3) and (3, 4). Find the centroid of the triangle. 


Find the mid-point of the line segment joining the points

`(1/2, (-3)/7)` and `(3/2, (-11)/7)`


If the mid-point (x, y) of the line joining (3, 4) and (p, 7) lies on 2x + 2y + 1 = 0, then what will be the value of p?


Point P is the centre of the circle and AB is a diameter. Find the coordinates of points B if coordinates of point A and P are (2, – 3) and (– 2, 0) respectively.


Given: A`square` and P`square`. Let B (x, y)

The centre of the circle is the midpoint of the diameter.

∴ Mid point formula,

`square = (square + x)/square`

⇒ `square = square` + x

⇒ x = `square - square`

⇒ x = – 6

and `square = (square + y)/2`

⇒ `square` + y = 0

⇒ y = 3

Hence coordinates of B is (– 6, 3).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×