Advertisements
Advertisements
प्रश्न
उत्तर
Moment of force = 10 N m
Force = 20 N
Distance = ?
Moment of force = Force × Distance
10 = 20 × Distance
Distance = `10/20` = 0.5 m
APPEARS IN
संबंधित प्रश्न
A force is applied on (i) a non-rigid body and (ii) a rigid body. How does the effect of the force differ in the above two cases?
Thrust is the ............ force acting on a surface.
What do you mean by the clockwise and anti-clockwise moment of force?
Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force.
A, B and C are the three forces each of magnitude 4 N acting in the plane of the paper as shown in Figure. The point O lies in the same plane.
- Which force has the least moment about O? Give a reason.
- Which force has the greatest moment about O? Give a reason.
- Name the forces producing
(a) Clockwise
(b) anticlockwise moments. - What is the resultant torque about the point O?
Fig. shows a uniform meter scale weighing 100 N pivoted at its centre. Two weights of 500 N and 300 N are hung from the ruler as shown in fig.
(i) Calculate total clockwise and anticlockwise moments.
(ii) Calculate difference in clockwise moment and anticlockwise moment.
(iii) Calculate the distance from O where a 100 N weight should be suspended to balance the meter scale.
State whether the moment of force is a scalar or vector quantity?
Under what condition will a set of gears produce a gain in torque.
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
