Advertisements
Advertisements
प्रश्न
The normal body temperature is 98.6°F. When Savitri was ill her temperature rose to 103.1°F. How many degrees above normal was that?
उत्तर
Given, normal body temperature = 98.6°F
And temperature rise to = 103.1°F
∴ Rise in temperature = (103.1 – 98.6)°F = 4.5°F
APPEARS IN
संबंधित प्रश्न
Subtract:
`6/14 - 2/7`
Subtract the following.
`5/10 - 3/10`
Subtract the following.
`8/15 - 2/15`
Subtract `8 1/3` from `100/9`.
Subtract `1 1/4` and `6 1/2`.
Solve:
`7/7 - 5/7`
Fill in the missing fraction.
`☐ - 3/6 = 3/6`
Fill in the boxes:
`☐ - 1/5 = 1/2`
Nandini’s house is `9/10` km from her school. She walked some distance and then took a bus for `1/2` km to reach the school. How far did she walk?
In her science class, Jyoti learned that the atomic weight of Helium is 4.0030; of Hydrogen is 1.0080; and of Oxygen is 16.0000. Find the difference between the atomic weights of Oxygen and Helium
