Question

The order of stability of the following resonating structures is:

\[\begin{array}{cc}
\phantom{.........}\ce{O}\\
\phantom{.........}||\\
\ce{\underset{(I)}{CH2 = CH - C - H}}
\end{array}\]

\[\begin{array}{cc}
\phantom{.........}\ce{\overset{⊕}{O}}\\
\phantom{.........}|\\
\ce{\underset{(II)}{\overset{⊕}{C}H2 - CH = C - H}}
\end{array}\]

\[\begin{array}{cc}
\phantom{.........}\ce{\overset{⊕}{O}}\\
\phantom{.........}|\\
\ce{\underset{(III)}{\overset{Θ}{C}H2 - CH = C - H}}
\end{array}\]

विकल्प

• II > I > III

• I > III > II

• I > II > III

• III > II > I

Answer 1

I > II > III

Explanation:

Because I is neutral, the most stable neutral resonating structure outperforms the ionic form. Carbon with an II + ve charge (less E.N. atom). The charge on oxygen in III + ve (more E.N. atom).