Question

The osmotic pressure of a solution of cane sugar was found to be 2.46 atm at 300 K. If the solution was diluted five times, calculate the osmotic pressure at the same temperature.
How can the osmotic pressure of the given cane sugar solution be decreased without changing its volume? Give a reason for your answer.

Answer 1

π = `(n_2/V) RT`

Given π = 2.64 atm

Let V₁ = V

V₂ = 5V  ...(On dilution by 5 times)

`(pi1)/(pi2) = ("n"//"V"_1)/("n"//"V"_2)`

`2.64/(pi2) = ("n"//"V")/("n"//"5V")`

π2 = 0.528 atm

Osmotic pressure is directly proportional to temperature.

The osmotic pressure of cane sugar can be decreased by decreasing the temperature.