Question

The path length of oscillation of simple pendulum of length 1 meter is 16 cm. Its maximum velocity is ______. (g = π² m/s²)

विकल्प

• 2π cm/s

• 4π cm/s

• 8π cm/s

• 16π cm/s

Answer 1

The path length of oscillation of simple pendulum of length 1 meter is 16 cm. Its maximum velocity is 8π cm/s. (g = π² m/s²)

Explanation:

Given: Path length = 16 cm

.·.  Amplitude a = `16/2` = 8 cm

Time period T = 2π`sqrt("l"/"g")`

= 2π`sqrt(1/pi^2)=2pixx1/pi=2"s"`

Maximum velocity V_max = aω

= `("a"xx2pi)/"T"`

= `8xx(2pi)/2`

= 8π cm/s