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प्रश्न
The p.d.f of c.r.v X is given by f(x) = `("x" + 2)/18`, if −2 < x < 4 = 0, otherwise = 0, then P[|x| < 1] = ____________.
विकल्प
`2/9`
`4/9`
`1/9`
`1/18`
MCQ
रिक्त स्थान भरें
उत्तर
The p.d.f of c.r.v X is given by f(x) = `("x" + 2)/18`, if −2 < x < 4 = 0, otherwise = 0, then P[|x| < 1] = `underline(2/9)`.
Explanation:
We have, f(x) = `[(("x" + 2)/18, -2 < "x" < 4), (0, "otherwise")]`
P[|x| < 1] = `int_-1^1 (("x" + 2)/18) "dx"`
= `1/18 ["x"^2/2 + 2"x"]_-1^1`
= `1/18 [(1/2 + 2) - (1/2 - 2)]`
= `4/18`
= `2/9`
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