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प्रश्न
The period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside mine will be ______.
विकल्प
increases
decreases
no change
None
MCQ
रिक्त स्थान भरें
उत्तर
The period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside mine will be increases.
Explanation:
Value of g decreases on going below earth's surface `"T" ∝ 1/sqrt"g"`. With depth g decreases according to the relation g' = `"g"[1 - "d"/"R"]`. If g decreases, Time period increases.
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