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प्रश्न
उत्तर
Pitch of the screw gauge = 0.5mm = 0.05 cm
Circular scale divisions = 100
Least Count of screw gauge = pitch of the gauge/circular scale divisions
= 0.05/100
= 0.0005cm
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संबंधित प्रश्न
Define the term 'Vernier constant'.
State one use of a screw gauge.
The diameter of a thin wire can be measured by
Why is the metre length in terms of the wavelength of light considered more accurate?
State the correction if the positive error is 7 divisions when the least count is 0.01 cm.
A micrometre screw gauge having a positive zero error of 5 divisions is used to measure diameter of a wire, when reading on the main scale is 3rd division and the 48th circular scale division coincides with baseline. If the micrometer has 10 divisions to a centimetre on the main scale and 100 divisions on a circular scale, calculate
- Pitch of screw
- Least count of screw
- Observed diameter
- Corrected diameter.
A micrometre screw gauge has a positive zero error of 7 divisions, such that its main scale is marked in 1/2 mm and the circular scale has 100 divisions. The spindle of the screw advances by 1 division complete rotation.
If this screw gauge reading is 9 divisions on the main scale and 67 divisions on the circular scale for the diameter of a thin wire, calculate
- Pitch
- L.C.
- Observed diameter
- Corrected diameter
What do you understand by the following term as applied to micrometre screw gauge?
Baseline
