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प्रश्न
The position vector of 1 kg object is `vecr = (3hati - hatj)` m and its velocity `vecv = (3hati + hatk)` ms-1. The magnitude of its angular momentum is `sqrtx` Nm where x is ______.
विकल्प
90
91
92
93
MCQ
रिक्त स्थान भरें
उत्तर
The position vector of 1 kg object is `vecr = (3hati - hatj)` m and its velocity `vecv = (3hati + hatk)` ms-1. The magnitude of its angular momentum is `sqrtx` Nm where x is 91.
Explanation:
Angular momentum, `vecL = m(vecr xx vecv)`
= `1[(3hati - hatj) xx (3hatj + hatk)] = (9hatk - 3hatj - hati)` NS
`|vecL| = sqrt(9^2 + (-3)^2 + (-1)^2) = sqrt91` Ns
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