Question

The potential difference between points B and E of the circuits is ______.

 

विकल्प

• `((C_2 - C_1))/V`

• `((C_4 - C_3))/V`

• `{(C_2C_3 - C_1C_4)/(C_1 + C_2 + C_3 + C_4)}V`

• `{(C_1C_4 - C_3C_2)/((C_1 + C_2)(C_3 + C_4))}V`

Answer 1

The potential difference between points B and E of the circuits is `underlinebb({(C_1C_4 - C_3C_2)/((C_1 + C_2)(C_3 + C_4))}V)`.

Explanation:

Charge on C₁ and C₂

`Q_1 = Q_2 = ((C_1C_2)/(C_1 + C_2))V`

and charge on C₃ and C₄

`Q_3 = Q_4 = ((C_3C_4)/(C_3 + C_4))V`

So, `V_B - V_E = Q_2/C_2 - Q_4/C_4`

= `(C_1V)/(C_1 + C_2) - (C_3V)/(C_3 + C_4)`

= `{(C_1C_4 - C_2C_3)/((C_1 + C_2)(C_3 + C_4))}V`