Question

The pressure of a 1:4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?

विकल्प

• 0.8 × 10⁵ atm

• 0.008 Nm^–2

• 8 × 10⁴ Nm^–2

• 0.25 atm

Answer 1

8 × 104 Nm^–2 

Explanation:

Partial pressure of oxygen, 

PO₂ = XO₂ × Ptotal

Mole fraction of \[\ce{O2}\] (XO₂) = `"Mole of oxygen"/("Mole of oxygen" + "Mole of hydrogen")`

= `4/(4 + 1) = 4/5`

PO₂ = `4/5 xx 1 = 4/5` = 0.8 atm  ......(∵ P_total = 1 atm)

1 atm = 1.1034 × 10⁵ Nm^–2 or Pa

∴ Partial pressure of dioxygen = 0.8 ×105 = 8 × 104 Nm^–2