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The probability density function of X is given byeforforf(x)={ke-x3for x>00for x≤0Find P(X ≤ 4) - Mathematics

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प्रश्न

The probability density function of X is given by
`f(x) = {(k"e"^(- x/3), "for"  x > 0),(0,"for"  x ≤ 0):}`
Find P(X ≤ 4)

योग

उत्तर

P(X ≤ 4) = `int_oo^4 (x)  "d"x`

= `k int_0^4 "e"^((-x)/3)  "d"x`

 `1/3["e"^((-x)/3)/((-1)/3)]_0^4`

= `- ("e"^((-4)/3) - 1)`

= `1 - "e"^((-4)/3)`

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Continuous Distributions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Probability Distributions - Exercise 11.3 [पृष्ठ २०२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 11 Probability Distributions
Exercise 11.3 | Q 4. (v) | पृष्ठ २०२

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