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The Probability that a Non-leap Year Has 53 Sundays, is - Mathematics

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प्रश्न

The probability that a non-leap year has 53 sundays, is

विकल्प

  • \[\frac{2}{7}\]

  • \[\frac{5}{7}\]

  • \[\frac{6}{7}\]

  • \[\frac{1}{7}\]

MCQ

उत्तर

A non leap year

TO FIND: Probability that a non leap year has 53 Sundays.

Total number of days in non leap year is 365days

Hence number of weeks in a non leap year is  `365/7=52`  weeks and 1 day

In a non leap year we have 52 complete weeks and 1 day which can be any day of the week e.g. Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday To make 53 Sundays the additional day should be Sunday Hence total number of days is 7

Favorable day i.e. Sunday is 1 

`"We know that PROBABILITY" = "Number of favourable event" /"Total number of event"`

Hence probability that a non leap year has 53 Sundays is `1/7` 

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अध्याय 16: Probability - Exercise 16.4 [पृष्ठ ३८]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 16 Probability
Exercise 16.4 | Q 31 | पृष्ठ ३८

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