Question

The radius of curvature of road is 60 m. If angle of banking is 27°, find maximum speed with which vehicle can tum along this curve. . (g = 9.8 m/s²)

Answer 1

Given: r = 60 m, θ = 27°

To find: v =?

Formula: `v = sqrt (r g tantheta)`

∴ `v = sqrt (60xx 9.8 xx tan27°)`

`v = sqrt (60xx 9.8 xx 0.5095)`

`= sqrt (588xx 0.5095`

`= sqrt299.5`

∴ `v = 17.31`m/s