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प्रश्न
The ratio of the forces between two charges placed at a certain distance apart in the air and by the same distance apart in a medium of dielectric constant K is ______.
विकल्प
1 : K2
K : 1
K2 : 1
1 : K
MCQ
रिक्त स्थान भरें
उत्तर
The ratio of the forces between two charges placed at a certain distance apart in the air and by the same distance apart in a medium of dielectric constant K is K : 1.
Explanation:
The force between two charges in the air,
`F_1 = 1/(4piε_0) . (q_1q_2)/r^2` ..............(i)
Similarly, the force between them in the medium of dielectric constant K.
`F_2 = 1/(4piε_0K) (q_1q_2)/r` ..............(ii)
From Eqs. (i) and (ii), we get,
F1/F2 = K ⇒ F1 : F2 = K : 1
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