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The reaction between the red lead and hydrochloric acid is given below: PbA3OA4+8HCl⟶3PbClA2+4HA2O+ClA2 Calculate the volume of the chlorine evolved at S.T.P. - Chemistry

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प्रश्न

The reaction between the red lead and hydrochloric acid is given below:

\[\ce{Pb3O4 + 8HCl -> 3PbCl2 + 4H2O + Cl2}\]

Calculate the volume of the chlorine evolved at S.T.P.

संख्यात्मक

उत्तर

1 V Pb3O4 produces 1 V Cl2

685g of Pb3O4has volume = 22.4 litres = volume of Cl2 produced

So, 6.85 Pb3O4 will produce = `(6.85 xx 22.4)/685` = 0.224 litres

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अध्याय 5: Mole concept and Stoichiometry - Exercise 5D [पृष्ठ ९४]

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सेलिना Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
Exercise 5D | Q 4.3 | पृष्ठ ९४

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