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प्रश्न
The SELECT statement when combined with the ______ clause returns records without repetition.
विकल्प
DESCRIBEUNIQUEDISTINCTNULL
उत्तर
The SELECT statement when combined with the DISTINCT clause returns records without repetition.
Explanation:
The distinct values from a collection of values in a table field are returned by the DISTINCT clause.
संबंधित प्रश्न
Which of the following is not a comparison query?
Which function is used with the ORDER BY clause to custom sort order?
Consider the following SQL.
SELECT ______ FROM Employee WHERE Dept= 'Printing';
Which of the following should be used to find the mean of the salary?
Which of the following is not true for SQL?
Which of the following is not a constraint?
Which constraint ensures that a column cannot have NULL values where NULL means missing/unknown/not applicable value?
How will you retrieve all details of employee_detail table?
______ operator defines the range of values in which the common value must fall into to make condition true.
Consider the following MOVIE table and write the SQL query based on it.
| MovieID | MovieName | Category | ReleaseDate | ProductionCost | BusinessCost |
| 001 | Hindi_Movie | Musical | 2018-04-23 | 124500 | 130000 |
| 002 | Tamil_Movie | Action | 2016-05-17 | 112000 | 118000 |
| 003 | English_Movie | Horror | 2017-08-06 | 245000 | 360000 |
| 004 | Bengali_Movie | Adventure | 2017-01-04 | 72000 | 100000 |
| 005 | Telugu_Movie | Action | - | 100000 | - |
| 006 | Punjabi_Movie | Comedy | - | 30500 | - |
- Display all the information from the Movie table.
- List business is done by the movies showing only MovieID, MovieName, and Total_Earning. Total_ Earning to be calculated as the sum of ProductionCost and BusinessCost.
- List the different categories of movies.
- Find the net profit of each movie showing its MovieID, MovieName, and NetProfit. Net Profit is to be calculated as the difference between Business Cost and Production Cost.
- List MovieID, MovieName, and Cost for all movies with ProductionCost greater than 10,000 and less than 1,00,000.
- List details of all movies which fall in the category of comedy or action.
- List details of all movies which have not been released yet.
Consider the following MOVIE table and write the SQL query based on it.
| MovieID | MovieName | Category | ReleaseDate | ProductionCost | BusinessCost |
| 001 | Hindi_Movie | Musical | 2018-04-23 | 124500 | 130000 |
| 002 | Tamil_Movie | Action | 2016-05-17 | 112000 | 118000 |
| 003 | English_Movie | Horror | 2017-08-06 | 245000 | 360000 |
| 004 | Bengali_Movie | Adventure | 2017-01-04 | 72000 | 100000 |
| 005 | Telugu_Movie | Action | - | 100000 | - |
| 006 | Punjabi_Movie | Comedy | - | 30500 | - |
List business is done by the movies showing only MovieID, MovieName, and Total_Earning. Total_ Earning to be calculated as the sum of ProductionCost and BusinessCost.
Consider the following MOVIE table and write the SQL query based on it.
| MovieID | MovieName | Category | ReleaseDate | ProductionCost | BusinessCost |
| 001 | Hindi_Movie | Musical | 2018-04-23 | 124500 | 130000 |
| 002 | Tamil_Movie | Action | 2016-05-17 | 112000 | 118000 |
| 003 | English_Movie | Horror | 2017-08-06 | 245000 | 360000 |
| 004 | Bengali_Movie | Adventure | 2017-01-04 | 72000 | 100000 |
| 005 | Telugu_Movie | Action | - | 100000 | - |
| 006 | Punjabi_Movie | Comedy | - | 30500 | - |
List MovieID, MovieName, and Cost for all movies with ProductionCost greater than 10,000 and less than 1,00,000.
Consider the following MOVIE table and write the SQL query based on it.
| MovieID | MovieName | Category | ReleaseDate | ProductionCost | BusinessCost |
| 001 | Hindi_Movie | Musical | 2018-04-23 | 124500 | 130000 |
| 002 | Tamil_Movie | Action | 2016-05-17 | 112000 | 118000 |
| 003 | English_Movie | Horror | 2017-08-06 | 245000 | 360000 |
| 004 | Bengali_Movie | Adventure | 2017-01-04 | 72000 | 100000 |
| 005 | Telugu_Movie | Action | - | 100000 | - |
| 006 | Punjabi_Movie | Comedy | - | 30500 | - |
List details of all movies which fall in the category of comedy or action.
Using the sports database containing two relations (TEAM, MATCH_DETAILS) and write the Query for the following:
- Display the MatchID of all those matches where both teams have scored more than 70.
- Display the MatchID of all those matches where FirstTeam has scored less than 70 but SecondTeam has scored more than 70.
- Display the MatchID and date of matches played by Team 1 and won by it.
- Display the MatchID of matches played by Team 2 and not won by it.
- Change the name of the relation TEAM to T_DATA. Also, change the attributes TeamID and TeamName to T_ID and T_NAME respectively.
Using the sports database containing two relations (TEAM, MATCH_DETAILS) and write the Query for the following:
Display the MatchID of all those matches where FirstTeam has scored less than 70 but SecondTeam has scored more than 70.
Using the sports database containing two relations (TEAM, MATCH_DETAILS) and write the Query for the following:
Display the MatchID of matches played by Team 2 and not won by it.
Consider the following tables – Bank_Account and Branch:
Table: Bank_Account
| ACode | Name | Type |
| A01 | Amrita | Savings |
| A02 | Parthodas | Current |
| A03 | Miraben | Current |
Table: Branch
| ACode | City |
| A01 | Delhi |
| A02 | Mumbai |
| A01 | Nagpur |
What will be the output of the following statement?
SELECT * FROM Bank_Account NATURAL JOIN Branch;
______ clause is used with a SELECT statement to display data in a sorted form with respect to a specified column.
Write the output of the queries (i) to (iv) based on the table, WORKER given below:
TABLE: WORKER
| W_ID | F_NAME | L_NAME | CITY | STATE |
| 102 | SAHIL | KHAN | KANPUR | UTTAR PRADESH |
| 104 | SAMEER | PARIKH | ROOP NAGAR | PUNJAB |
| 105 | MARY | JONES | DELHI | DELHI |
| 106 | MAHIR | SHARMA | SONIPAT | HARYANA |
| 107 | ATHARVA | BHARDWAJ | DELHI | DELHI |
| 108 | VEDA | SHARMA | KANPUR | UTTAR PRADESH |
SELECT F_NAME, CITY FROM WORKER ORDER BY STATE DESC;SELECT DISTINCT (CITY) FROM WORKER;SELECT F_NAME, STATE FROM WORKER WHERE L_NAME LIKE '_HA%';SELECT CITY, COUNT(*) FROM WORKER GROUP BY CITY;
