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प्रश्न
The slope of frequency of incident light and stopping potential for a given surface will be
विकल्प
h
h/e
eh
e
MCQ
उत्तर
h/e
Explanation:
evs = hv – wo or Vs = `(hv)/e - (Wo)/e`
S10/z of V and Vs is h/e.
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