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प्रश्न
The smallest number which when diminished by 3 is divisible by 14, 28, 36 and 45, is
विकल्प
1257
1260
1263
none of these
उत्तर
1263
The smallest number that is exactly divisible by 14, 28, 36, and 45 will be their L.C.M.
So, the required number will be L.C.M. plus 3.
L.C.M. of the three numbers = 22 × 32 × 5 × 7
= 1260
∴ Required number = 1260 + 3 = 1263
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