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The students of a Vidyalaya were asked to participate in a competition for making and decorating penholders in the shape of a cylinder with a base, using cardboard. Each penholder was to be of radius 3 cm and height 10.5 cm. - Mathematics

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प्रश्न

The students of a Vidyalaya were asked to participate in a competition for making and decorating penholders in the shape of a cylinder with a base, using cardboard. Each penholder was to be of radius 3 cm and height 10.5 cm. The Vidyalaya was to supply the competitors with cardboard. If there were 35 competitors, how much cardboard was required to be bought for the competition?

`["Assume "pi=22/7]`

 

उत्तर

Radius (r) of the circular end of cylindrical penholder = 3 cm

Height (h) of penholder = 10.5 cm

Surface area of 1 penholder = CSA of penholder + Area of base of penholder

= 2πrh + πr2

`=[2xx22/7xx3xx10.5+22/7xx(3)^2]cm^2`

`=(132xx1.5+198/7)cm^2`

`=(198+198/7)cm^2`

`=1584/7cm^2`

`"Area of cardboard sheet used by 1 competitor "=1584/7cm^2`

Area of cardboard sheet used by 35 competitors

`=(1584/7xx35)cm^2=7920cm^2`

Therefore, 7920 cm2 cardboard sheet will be bought.

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अध्याय 13: Surface Area and Volumes - Exercise 13.2 [पृष्ठ २१७]

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एनसीईआरटी Mathematics [English] Class 9
अध्याय 13 Surface Area and Volumes
Exercise 13.2 | Q 11 | पृष्ठ २१७

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