Question

The sum of the digits of the digits of two digit number is 5. If the digits are reversed, the number is reduced by 27. Find the number.

Answer 1

Let the digit at unit’s place be x and the digit at ten’s place y.
Required no. = 10y + x
If the digit’s are reversed,
Reversed no. = 10x + y

According to the question,
x + y = 5                             ...(1)
and,
(10y + x) - (10x + y) = 27
9y - 9x = 27
y - x = 3                             ...(2)
Now,
Adding equation (1) and (2),
         y - x = 3                  ....(2)
   +   y + x = 5                 ....(1)
        2y = 8
         y = 4

From (1)
x + 4 = 5
x = 1
Require no is
10 (4) + 1 = 41