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प्रश्न
The sum of three consecutive multiples of 11 is 363. Find these multiples.
योग
उत्तर
If x is a multiple of 11, the next multiple is x + 11. The next to this is x + 11 + 11 or x + 22.
So we can take three consecutive multiples of 11 as x, x+ 11, and x+ 22.
So we can take three consecutive multiples of 11 as x, x+ 11, and x+ 22.

It is given that the sum of these consecutive multiples of 11 is 363.
x + (x + 11) + (x + 22) = 363
or x + x + 11 + x + 22 = 363.
or 3x + 33 = 363.
or 3x = 363 - 33
or 3x = 330
or x = `330/3`
or x = 110
hence, the three consecutive multiples are 110, 121, 132.
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