Question

The table below gives some bowling figures related to a cricket match.

Bowler	Overs	Runs given	Wickets taken
Chandrakant		18	4
Ramakant		20	-
Ahmed		12	2

Scale: 1 picture = 1 over (6 balls)

Answer the following questions by referring to the table above.

1. About how many bowlers does the table give information?
2. Who gave away the most runs?
3. How many overs did Chandrakant bowl?
4. How many wickets did Ramakant take?
5. How many balls did Ahmed bowl?
6. How many runs did Chandrakant give?
7. How many overs were bowled altogether?
8. Who gave away the least runs per over?

Answer 1

1. The table gives information about 3 bowlers: Chandrakant, Ramakant, and Ahmed.
2. Ramakant gave away the most runs, which is 20 runs.
3. Chandrakant bowled 4 overs (4 blue balls in the table).
4. Ramakant took 0 wickets (no value under "Wickets taken").
5. Ahmed bowled 2 overs, and since each over consists of 6 balls:
   2 × 6 = 12 balls.
   Ahmed bowled 12 balls.
6. Chandrakant gave 18 runs.
7. Adding the overs bowled by each:
   • Chandrakant: 4 overs
   • Ramakant: 3 overs
   • Ahmed: 2 overs
   • Total overs = 4 + 3 + 2 = 9
     Altogether, 9 overs were bowled.
8. Calculate runs per over for each:
   
   • Chandrakant: `18/4` = 4.5 runs per over.
   • Ramakant: `20/3` ≈ 6.67 runs per over.
   • Ahmed: `12/2` = 6 runs per over.
     Chandrakant gave away the least runs per over, at 4.5 runs per over.