Advertisements
Advertisements
प्रश्न
The time periods of two pendulums are 1.44 s and 0.36 s respectively. Calculate the ratio of their lengths.
उत्तर
`"T"_1` = 1.44 s;
`"T"_2` = 0.36 s
Let l1 and l2 be the lengths of the two pendulums.
`"T"_1/"T"_2=sqrt("l"_1/"l"_2)`
`sqrt("l"_1/"l"_2)=1.44/0.36=144/36=4/1`
Squaring both sides,
`(sqrt(("l"_1)/"l"_2))^2=(4/1)^2`
⇒ `"l"_1/"l"_2=16/1`
APPEARS IN
संबंधित प्रश्न
Find the length of a second's pendulum at a place where g = 10 m s-2 (Take π = 3.14)
A student finds that the boiling point of water in a particular experiment is 97.8°C. If the actual boiling point of water is 99.4°C, calculate the percentage error.
Length of the second’s pendulum is 100 cm. Find the length of another pendulum whose time period is 2.4 s.
The time period of the two pendulums are 2 s and 3 s respectively. Find the ratio of their lengths.
What do you understand by frequency of oscillations of simple pendulum?
State the two ratios of a scale, which are not suitable for plotting points.
State two important precautions for drawing a graph line.
What do you mean by light year?
