Advertisements
Advertisements
प्रश्न
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find its perimeter.
उत्तर
Adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2
∴ Perimeter = 2(2x2 – 5xy + 3z2 + 4xy – x2 – z2)
= 4x2 – 10xy + 6z2 + 8xy – 2x2 – 2z2
= 2x2 – 2xy + 4z2
APPEARS IN
संबंधित प्रश्न
Add : 8x − 3y + 7z, −4x + 5y − 4z, −x − y − 2z
Find the total savings of a boy who saves ₹ (4x – 6y), ₹ (6x + 2y), ₹ (4y – x) and ₹ (y – 2x) for four consecutive weeks.
Subtract : −2x2y + 3xy2 from 8x2y
Subtract : 6a + 3 from a3 − 3a2 + 4a + 1
Subtract : a2 + ab + b2 from 4a2 − 3ab + 2b2
Take m2 + m + 4 from −m2 + 3m + 6 and the result from m2 + m + 1.
Subtract the sum of 5y2 + y – 3 and y2 – 3y + 7 from 6y2 + y – 2.
How much more than 2x2 + 4xy + 2y2 is 5x2 + 10xy – y2 ?
How much less 2a2 + 1 is than 3a2 – 6 ?
What must be subtracted from 19x4 + 2x3 + 30x – 37 to get 8x4 + 22x3 – 7x – 60 ?
