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प्रश्न
The value of `int_2^(π/2) sin^3x dx` = ______.
विकल्प
`1/3`
`4/3`
`2/3`
`8/3`
MCQ
रिक्त स्थान भरें
उत्तर
The value of `int_2^(π/2) sin^3x dx` = `underlinebb(2/3)`.
Explanation:
I = `int_2^(π/2) sin^3x dx`
= `int_0^(π/2) sin^2x sinx dx`
= `int_0^(π/2) (1 - cos^2x) sinx dx`
Put cos x = t
`\implies` sin x dx = – dt
When x = 0, t = 1
When x = `π/2`, t = 0
∴ I = `int_1^0 (1 - t^2)(-dt)`
= `int_1^0 (1 - t^2)(dt)`
= `[t - t^3/3]_1^0`
= `-[0 - (1 - 1/3)]`
= `2/3`
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Methods of Evaluation and Properties of Definite Integral
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