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प्रश्न
The value of θ in (π, 2π) satisfying the equation sin2θ - cos2θ = 1 is ______
विकल्प
`(5pi)/3`
`(5pi)/4`
`(3pi)/2`
`(7pi)/4`
MCQ
रिक्त स्थान भरें
उत्तर
The value of θ in (π, 2π) satisfying the equation sin2θ - cos2θ = 1 is `underline((3pi)/2)`.
Explanation:
sin2θ - cos2θ = 1
⇒ cos 2θ = -1
⇒ cos 2θ = cos π
⇒ 20 = 2nπ ± π ..........[∵ cos θ = cos α ⇒ θ = 2nπ ± α]
⇒ `theta = npi ± π/2`
⇒ `theta = (3pi)/2` .............[∵ θ ∈ (π, 2π)]
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Trigonometric Equations and Their Solutions
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