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प्रश्न
The value of `sin π/10` is ______.
विकल्प
`(-1 + sqrt(5))/4`
`(2 - sqrt(3))/2`
`(2 + sqrt(3))/2`
`(1 - sqrt(5))/4`
MCQ
रिक्त स्थान भरें
उत्तर
The value of `sin π/10` is `underlinebb((-1 + sqrt(5))/4)`.
Explanation:
`π/10` = 18°
Let, θ = 18°, 2θ = 36°, 3θ = 54°
We have, 2θ + 3θ = 90°
2θ = 90° – 3θ
∴ sin 2θ = sin(90° – 3θ)
2 sin θ . cos θ = cos 3θ
∴ 2 sin θ . cos θ = 4 . cos3 θ – 3 cos θ
2 sin θ = 4 . cos2 θ – 3
2 sin θ = 4(1 – sin2 θ) – 3
2 sin θ = 4 – 4 sin2 θ – 3
4 sin2 θ + 2 sin θ – 1 = 0
∴ sin θ = `(- 2 ± sqrt(4 + (4)(4)(1)))/(2(4)) = (-2 ± 2sqrt(5))/(2(4))`
∴ sin θ = `(-1 ± sqrt(5))/4`
∴ sin θ = `(-1 + sqrt(5))/4` ...[∵ θ is an acute angle]
∴ sin 18° = `(-1 + sqrt(5))/4`
shaalaa.com
Trigonometric Functions of Triple Angle
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