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प्रश्न
The value of `"tan"^-1 (1/2) + "tan"^-1(1/3) + "tan"^-1(7/8)` is ____________.
विकल्प
`"tan"^-1 (7/8)`
`"cot"^-1 (15)`
`"tan"^-1 (15)`
`"tan"^-1 (25/24)`
MCQ
रिक्त स्थान भरें
उत्तर
The value of `"tan"^-1 (1/2) + "tan"^-1(1/3) + "tan"^-1(7/8)` is `underline("tan"^-1 (15))`.
Explanation:
`"tan"^-1 (1/2) + "tan"^-1(1/3) + "tan"^-1(7/8)`
`= "tan"^-1 ((1/2 + 1/3)/(1 - 1/2 xx 1/3)) + "tan"^-1 (7/8)`
`= "tan"^-1 (5/5) + "tan"^-1 (7/8)`
`= "tan"^-1 (1) + "tan"^-1 (7/8)`
`= "tan"^-1 ((1 + 7/8)/(1 - 7/8))`
`= "tan"^-1 (15)`
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