हिंदी

The variance of first n natural numbers is ______. -

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प्रश्न

The variance of first n natural numbers is ______.

विकल्प

  • `(n(n + 1))/2`

  • `((n + 1)(n + 5))/12`

  • `((n + 1)(n - 5))/12`

  • `((n^2 - 1))/12`

MCQ
रिक्त स्थान भरें

उत्तर

The variance of first n natural numbers is `underlinebb(((n^2 - 1))/12)`.

Explanation:

Variance of first n natural numbers

= `(sumn^2)/n - ((sumn)/n)^2`

= `(n(n + 1)(2n + 1))/(6n) - ((n(n + 1))/(2n))^2`

= `(n + 1)[(2n + 1)/6 - ((n + 1))/4]`

= `((n + 1))/12[4n + 2 - 3n - 3]`

= `((n + 1))/12 xx (n - 1)`

= `(n^2 - 1)/12`

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Standard Deviation
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