Advertisements
Advertisements
प्रश्न
Three capacitors C1 = 3μF, C2 = 6μF, and C3 = 10μF are connected to a 50 V battery as shown in Figure below:
Calculate:
(i) The equivalent capacitance of the circuit between points A and B.
(ii) The charge on C1.
उत्तर
C1 = 3μF, C2 = 6μF, and C3 = 10μF
if V' be in equivalent capacitance between C1 and C2 then
`1/(C')=1/(C_1)+1/(C_2)`
=`1/3+1/6=3/6=1/2`
C' = 2πF
Now, CEq = C' +C3 = 2 +10
CEq = 12πF
(i) Eq, capacitance between A and B = 12πF
(ii) Charge at C1 = 2 ×10-6 × 50 C = 10- 4 C
APPEARS IN
संबंधित प्रश्न
Define capacitor reactance. Write its S.I units.
Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be
Find the equivalent capacitance of the infinite ladder shown in figure between the points A and B.
A capacitor of capacitance 10 μF is connected to a battery of emf 2 V. It is found that it takes 50 ms for the charge of the capacitor to become 12.6 μC. Find the resistance of the circuit.
Figure shows two parallel plate capacitors with fixed plates and connected to two batteries. The separation between the plates is the same for the two capacitors. The plates are rectangular in shape with width b and lengths l1 and l2. The left half of the dielectric slab has a dielectric constant K1 and the right half K2. Neglecting any friction, find the ration of the emf of the left battery to that of the right battery for which the dielectric slab may remain in equilibrium.
Consider the situation shown in figure. The plates of the capacitor have plate area A and are clamped in the laboratory. The dielectric slab is released from rest with a length a inside the capacitor. Neglecting any effect of friction or gravity, show that the slab will execute periodic motion and find its time period.
Derive the expression for resultant capacitance, when the capacitor is connected in series.
Calculate the resultant capacitances for each of the following combinations of capacitors.
