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Thrice a number decreased by 5 exceeds twice the number by 1. Find the number. - Mathematics

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प्रश्न

Thrice a number decreased by 5 exceeds twice the number by 1. Find the number.

योग

उत्तर

Let the number be x.

Then, thrice of this number = 3x and twice of this number = 2x.

If we decrease thrice of x by 5, we get (3x – 5)

According to the question,

(3x – 5) – (2x) = 1

⇒ 3x – 5 – 2x = 1

⇒ x – 5 = 1

⇒ x = 1 + 5   ......[Transposing (–5) to RHS]

⇒ x = 6

Hence, the required number is 6.

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अध्याय 4: Simple Equations - Exercise [पृष्ठ ११४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 7
अध्याय 4 Simple Equations
Exercise | Q 97. | पृष्ठ ११४

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