Question

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:

Sum	Frequency
2	14
3	30
4	42
5	55
6	72
7	75
8	70
9	53
10	46
11	28
12	15

If the dice are thrown once more, what is the probability of getting a sum more than 10?

Answer 1

Total number of times, when two dice are thrown simultaneously, n(S) = 500

Number of times of getting a sum more than 10, n(E₁) = 28 + 15 = 43

∴ Probability of getting sum more than 10 = `(n(E_1))/(n(S)) = 43/500` = 0.086

Hence, the probability of getting a sum more than 10 is 0.086