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प्रश्न
Two discs having moment of inertia I1 and I2 are made from same material have same mass. Their thickness and radii are t1, t2, and R1, R2 respectively. The relation between moment of inertia of each disc about an axis passing through its centre and perpendicular to its plane and its thickness is ______.
विकल्प
`I_1t_2^2=I_2t_1^2`
`I_1t_1=I_2t_2`
`I_1t_2=I_2t_1`
`I_1t_1^2=I_2t_2^2`
उत्तर
Two discs having moment of inertia I1 and I2 are made from same material have same mass. Their thickness and radii are t1, t2, and R1, R2 respectively. The relation between moment of inertia of each disc about an axis passing through its centre and perpendicular to its plane and its thickness is `underline(I_1t_1=I_2t_2)`.
Explanation:
`I_1=("mR"_1^2)/2` `m_1=piR_1^2t_1`
`I_2=("mR"_2^2)/2` `m_2=piR_2^2t_2`
`I_1/I_2=R_1^2/R_2^2=t_2/t_1` m1 = m2 `therefore R_1^2t_1=R_2^2t_2`
`thereforeI_1t_1=I_2t_2`