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प्रश्न
Two equal drops of water are falling through air with a steady velocity v. If the drops coalesce, the new velocity will be ______.
विकल्प
2v
`sqrt2"v"`
22/3v
`"v"/sqrt2`
MCQ
रिक्त स्थान भरें
उत्तर
Two equal drops of water are falling through air with a steady velocity v. If the drops coalesce, the new velocity will be 22/3v.
Explanation:
According to question,
vt ∝ r2
`4/3pi"R"^3=2xx4/3pi"r"^3`
⇒ R = 21/3r
∴ `"v"_2/"v"_1=("r"_2/"r"_1)^2`
= `("R"/"r")^2` = 22/3
⇒ v2 = 22/3v
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