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Two Resistors of 4 ω and 6 ω Are Connected in Parallel. the Combination is Connected Across a 6 Volt Battery of Negligible Resistance. Calculate: - Physics

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प्रश्न

Two resistors of 4 Ω and 6 Ω are connected in parallel. The combination is
connected across a 6 volt battery of negligible resistance. Calculate:
( i) The power supplied by the battery,
(ii) The power dissipated in each resistor.

संख्यात्मक

उत्तर

Total resistance of resitors of 4 Ω and 6 Ω in parallel is:

R= `[1/4 + 1/6]^-1 = 2.4 Omega`

Given voltage supply= 6 volt

(i) Power supplied by the battery, P = `"V"^2/"R" = (6 xx 6)/2.4` = 15 watt

(ii) Power dissipated in 4 Ω resistor, P = `"V"^2/"R" = (6 xx 6)/4` = 9 watt

Power dissipated in 6 Ω  resistor, P1  `"V"^2/"R" = (6 xx 6)/6` = 6 watt

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Current Electricity - Exercise 4.2 ii [पृष्ठ १८८]

APPEARS IN

फ्रैंक Physics - Part 2 [English] Class 10 ICSE
अध्याय 4 Current Electricity
Exercise 4.2 ii | Q 20 | पृष्ठ १८८

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