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प्रश्न
Two short magnets of equal dipole moments M are fastened perpendicularly at their centre in the Figure . The magnitude of the magnetic field at a distance d from the centre on the bisector of the right angle is
विकल्प
`(u_0)/(4pi) M/d^3`
`(u_0)/(4pi) (sqrt2M)/d^3`
`(u_0)/(4pi) (2sqrt2M)/d^3`
`(u_0)/(4pi) (2M)/d^3`
उत्तर
`(u_0)/(4pi) (2sqrt2M)/d^3`
Magnetic field (B1) due to the short dipole A of dipole moment M at an axial point is given by,
`vec B_1 = (u_0)/(4pi) (2M)/d^3` ....(1)
Magnetic field (B2) due to the short dipole B of dipole moment M at an axial point is given by,
`vec B_2 = (u_0)/(4pi) (2M)/d^3` ....(2)
Resultant magnetic field (B) will be,
`B = sqrt (B_1^2 + B_2^2)`
B = `(u_0)/(4pi) (2sqrt2M)/d^3`
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