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प्रश्न
Two simple pendulums A and B have lengths 1.0 m and 4.0 m, respectively, at a certain place. Which pendulum will make more oscillations in 1 min? Explain your answer.
उत्तर १
Pendulum A will take more time (twice) in a given time because the time period of oscillation is directly proportional to the square root of the length of the pendulum. Therefore, the pendulum B will have a greater time period and thus making lesser oscillations.
उत्तर २
A. The reason is that `"T" ∝ sqrt(l)` ∴ time period of B is more (twice) than that of A . Hence A will make more oscillations (twice) in a given time, than B.
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संबंधित प्रश्न
Define the terms : time period as related to a simple pendulum.
How is the time period of a simple pendulum affected, if at all, in the following situations:
- The length is made four times.
- The acceleration due to gravity is reduced to one-fourth.
State how does the time period of a simple pendulum depend on (a) length of pendulum, (b) mass of bob, (c) amplitude of oscillation and (d) acceleration due to gravity.
Explain how the frequency of oscillation is related to the length of a pendulum and the amplitude of its oscillation.
Two clocks A and B are shown in Figure 13.1. Clock A has an hour and a minute hand, whereas clock B has an hour hand, a minute hand as well as a second hand. Which of the following statement is correct for these clocks?
Give scientific reason.
In earlier times, people used to listen for the arrival of a distant train by putting their ear to the rail.
Give scientific reason.
In earlier times, people used to listen for the arrival of a distant train by putting their ear to the rail.
Give scientific reasons.
In earlier times, people used to listen for the arrival of a distant train by putting their ear to the rail.
Give scientific reason.
In earlier times, people used to listen for the arrival of a distant train by putting their ear to the rail.
You can perform an interesting activity when you visit a park to ride a swing. You will require a watch. Make the swing oscillate without anyone sitting on it. Find its time period in the same way as you did for the pendulum. Make sure that there are no jerks in the motion of the swing. Ask one of your friends to sit on the swing. Push it once and let it swing naturally. Again measure its time period. Repeat the activity with different persons sitting on the swing. Compare the time period of the swing measured in different cases. What conclusions do you draw from this activity?
