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Using binomial theorem, find the value of (9.9)3 - Mathematics and Statistics

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प्रश्न

Using binomial theorem, find the value of (9.9)3 

योग

उत्तर

(9.9)3 = (10 – 0.1)3

= 3C0 (10)3 (0.1)03C1 (10)2 (0.1)1 + 3C2 (10)1 (0.1)23C3 (10)0 (0.1)3

Since, 3C0 = 3C3 = 1, 3C1 = 3C2 = 3

∴ (9.9)3 = 1(1000)(1) – 3(100)(0.1) + 3(10)(0.01) – 1(1)(0.001)

= 1000 – 30 + 0.3 – 0.001

= 1000.3 – 30.001

= 970.299

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Binomial Theorem for Positive Integral Index
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Methods of Induction and Binomial Theorem - Exercise 4.2 [पृष्ठ ७७]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 4 Methods of Induction and Binomial Theorem
Exercise 4.2 | Q 6. (i) | पृष्ठ ७७
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