Advertisements
Advertisements
प्रश्न
Using prime factorization, find the HCF and LCM of 396, 1080 In case verify that HCF × LCM = product of given numbers.
उत्तर
Prime factorization:
396 = 22 × 32 × 11
1080 = 23 × 33 × 5
HCF = product of smallest power of each common prime factor in the numbers = 22 × 32 = 36
LCM = product of greatest power of each prime factor involved in the numbers = 23 × 33 × 5 × 11 = 11880
APPEARS IN
संबंधित प्रश्न
Find the HCF of the following pairs of integers and express it as a linear combination of 506 and 1155.
Show that every positive even integer is of the form (6m+1) or (6m+3) or (6m+5)where m is some integer.
Find the missing numbers in the following factorization:
Without actual division show that each of the following rational numbers is a non-terminating repeating decimal.
(i)`77/210`
If a and b are relatively prime, what is their LCM?
Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.
Every odd integer is of the form 2m − 1, where m is an integer (True/False).
The number of decimal place after which the decimal expansion of the rational number \[\frac{23}{2^2 \times 5}\] will terminate, is
Prove that two consecutive positive integers are always co-prime
Write whether every positive integer can be of the form 4q + 2, where q is an integer. Justify your answer.