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प्रश्न
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
उत्तर
Here, zero of the vernier scale lies on the right of the main scale.
Also, the 5th vernier division is coinciding with some main scale division
Thus, zero error = 0 + 5 x L.C. = -0.05 cm
Hence zero correction = 0.05 cm
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संबंधित प्रश्न
Fig., below shows the reading obtained while measuring the diameter of a wire with a screw gauge. The screw advances by 1 division on the main scale when circular head is rotated once.
Find:
(i) Pitch of the screw gauge,
(ii) Least count of the screw gauge and
(iii) The diameter of the wire.
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
What do you understand by the following term as applied to micrometre screw gauge?
Sleeve scale
How do you account for positive zero error for calculating the correct diameter of wires?
Explain the term least count of a screw gauge. How are they determined?
How will you measure the least count of vernier caliper?
Least count of a vernier caliper is ______ cm.
